## Pigeonhole Sort in Kotlin

Pigeonhole sorting is a sorting algorithm that is suitable for sorting lists of elements where the number of elements and the number of possible key values are approximately the same

Pigeonhole sorting is a sorting algorithm that is suitable for sorting lists of elements where the number of elements and the number of possible key values are approximately the same.

It requires O(n + Range) time where n is number of elements in input array and â€˜Rangeâ€™ is number of possible values in array.

It is similar to counting sort, but differs in that it moves items twice: once to the bucket array and again to the final destination

Shell Sort

#### Working of Algorithm :

• Find minimum and maximum values in array. Let the minimum and maximum values be â€˜minâ€™ and â€˜maxâ€™ respectively. Also find range as â€˜max-min-1â€™.
• Set up an array of initially empty â€œpigeonholesâ€? the same size as of the range.
• Visit each element of the array and then put each element in its pigeonhole. An element arr[i] is put in hole at index arr[i] â€“ min.
• Start the loop all over the pigeonhole array in order and put the elements from non- empty holes back into the original array.

Bubble Sort Complete code for Pigeonhole sort in kotlin

``````
import java.util.Arrays

fun pigeonhole_sort(arr: IntArray, n: Int):IntArray {
var min = arr[0]
var max = arr[0]
val range: Int
var i: Int
var j: Int
var index: Int

for (a in 0 until n) {
if (arr[a] > max)
max = arr[a]
if (arr[a] < min)
min = arr[a]
}

range = max - min + 1
val phole = IntArray(range)
Arrays.fill(phole, 0)

i = 0
while (i < n) {
phole[arr[i] - min]++
i++
}

index = 0

j = 0
while (j < range) {
while (phole[j]-- > 0)
arr[index++] = j + min
j++
}
return arr

}

fun main(args: Array<String>) {
val l = intArrayOf(-2, 0, -2, 5, 5, 3, -1, -3, 5, 5, 0, 2, -4, 4, 2)
println(pigeonhole_sort(l, l.size).contentToString())
}
``````

Output of the Pigeonhole sort in kotlin

``````
[-4, -3, -2, -2, -1, 0, 0, 2, 2, 3, 4, 5, 5, 5, 5]
``````

Cocktail Sort

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