CCNA 200-125 And CCENT Practice Pack Subnetting Success! Set 2

What is the tightest (shortest) mask you can put onto any Class A network and leave yourself a minimum of 250 valid subnets with which to work?


Options are :

  • 255.0.0.0
  • 255.255.192.0
  • 255.255.252.0
  • 255.192.0.0
  • 255.255.255.0
  • 255.255.0.0

Answer :255.255.0.0

Certification : CCNA Cyber Ops - SECOPS # 210-255

How many valid host IP addresses exist on each subnet when 132.14.0.0 is subnetted with a /22 mask?


Options are :

  • 2048
  • 1024
  • 1022
  • 2046
  • 510
  • 512

Answer :1022

You've just subnetted the 147.33.0.0 network with a /19 mask.   How many valid subnets do you have to work with?


Options are :

  • 6
  • 16
  • 126
  • 14
  • 128
  • 8

Answer :8

What is the broadcast address for the 211.24.32.0 255.255.255.192 subnet?


Options are :

  • 211.24.32.127 /28
  • 211.24.32.31 /28
  • 211.24.32.64 /26
  • 211.24.32.63 /26
  • 211.24.32.254 /27
  • 211.24.32.255 /27

Answer :211.24.32.63 /26

CCNA ICND1 Practice

Which of these subnets contains the IP address 172.18.49.200 / 27?


Options are :

  • 172.18.49.0 255.255.255.240
  • 172.18.49.192 255.255.255.224
  • 172.18.49.128 255.255.255.240
  • 172.18.49.192 255.255.255.240
  • 172.18.49.0 255.255.255.224
  • 172.18.49.128 255.255.255.224

Answer :172.18.49.192 255.255.255.224

Which three of these addresses can be found on the 144.13.26.0 /27 subnet?


Options are :

  • 144.13.26.14
  • 144.13.26.2
  • 144.13.26.31
  • 144.13.26.32
  • 144.13.26.30
  • 144.13.62.1

Answer :144.13.26.14 144.13.26.2 144.13.26.30

What is the minimum number of host bits necessary when the subnets on your network must contain at least 128 hosts?


Options are :

  • 10
  • 7
  • 8
  • 9
  • 6
  • 5

Answer :8

Certification : CCNA Cyber Ops - SECOPS # 210-255

When applied to a Class C network, the subnet mask 255.255.255.224 results in how many valid IP addresses per subnet?


Options are :

  • 30
  • 32
  • 128
  • 64
  • 126
  • 62

Answer :30

What is the broadcast address for the subnet 17.200.14.0 /25?


Options are :

  • 17.200.255.255 /25
  • 17.200.14.255 /25
  • 17.200.14.63 /25
  • 17.200.14.127 /25
  • 17.200.14.1 /25
  • 17.200.14.128 /25

Answer :17.200.14.127 /25

Your boss just subnetted the 148.4.0.0 network with a 255.255.255.128 mask.   He then asks you to check his math.  How many valid host addresses will you have on each subnet?


Options are :

  • 256
  • 126
  • 128
  • 64
  • None of these choices is the correct answer.
  • 62
  • 254

Answer :126

Practice : CCNA Cyber Ops - SECOPS # 210-255

What is the tightest (shortest) mask you can put on the 130.17.0.0 network while allowing yourself 60 valid subnets?


Options are :

  • 255.255.255.252
  • 255.255.128.0
  • 255.255.0.0
  • 255.255.252.0
  • 255.255.192.0
  • 255.252.0.0

Answer :255.255.252.0

Given the 17.0.0.0 /14 network, how many valid subnets do we have to work with?


Options are :

  • 62
  • 64
  • 96
  • 128
  • 126
  • 94

Answer :64

Your boss plans on subnetting the 222.1.1.0 network with a /28 mask.   She asks your opinion.    What should you tell her?


Options are :

  • It's a solid plan that will leave you with the same number of valid subnets and valid host addresses on each of those subnets.
  • It's an illegal plan, since you can't subnet that particular subnet with a /28 mask.
  • It's a terrific plan as long as you're happy with 32 valid subnets and 14 valid host addresses on each of those subnets.
  • It's a good plan that will leave you with 16 valid subnets and 14 valid host addresses on each subnet.

Answer :It's a good plan that will leave you with 16 valid subnets and 14 valid host addresses on each subnet.

Certification : CCNA Cyber Ops - SECOPS # 210-255

Upon which of these subnets will you find the IP address 222.22.2.2 /22?


Options are :

  • 222.22.0.0 /16
  • 222.0.0.0 /22
  • 222.22.0.0 /24
  • 222.22.0.0 /22
  • 222.22.2.0 /22

Answer :222.22.0.0 /22

Upon what subnet will you find the IP address 24.7.32.89 / 14?


Options are :

  • 24.2.0.0 /14
  • 24.7.32.0 /14
  • 24.4.0.0 /14
  • 24.6.0.0 /14
  • 24.0.0.0 /14

Answer :24.4.0.0 /14

Convert the decimal 148 to a binary string.


Options are :

  • 10001110
  • 10010100
  • 10011000
  • 01111110
  • 10011100
  • 01111111

Answer :10010100

Certification : CCNA Cyber Ops - SECOPS # 210-255

You've been given the 11.0.0.0 network with a /12 mask.   How many valid subnets do you have to work with?


Options are :

  • 6
  • 14
  • 62
  • 32
  • 8
  • 30
  • 64
  • 16

Answer :16

You're about to subnet the 221.13.7.0 network with a /28 mask.    Doing that will leave you with how many valid subnets to work with?


Options are :

  • 128
  • 16
  • 6
  • 14
  • 32
  • 8
  • 126
  • 30

Answer :16

What is the decimal equivalent of the binary string 00001110?


Options are :

  • 24
  • 15
  • 17
  • 25
  • 9
  • 14

Answer :14

Certification : CCNA Cyber Ops - SECOPS # 210-255

Given the following network and mask, how many valid IP addresses reside on each subnet?

39.0.0.0 /26


Options are :

  • 4
  • 32
  • 128
  • 62
  • This is an illegal subnet mask for this network.
  • 2
  • 126
  • 30
  • 64

Answer :62

The major network number 14.0.0.0 has been subnetted with a 255.255.252.0 mask.   How many valid IP addresses can you hand out on each subnet?


Options are :

  • 4
  • 512
  • 1024
  • 1022
  • 2048
  • 510
  • 2
  • 2046

Answer :1022

The 15.5.0.0 network has been subnetted with a /27 mask.   How many valid host addresses reside on each subnet?


Options are :

  • 32
  • 128
  • 4094
  • 16
  • 30
  • 4096
  • 126
  • 14

Answer :30

Certification : CCNA Cyber Ops - SECOPS # 210-255

A senior admin at your network has subnetted the 178.14.0.0 network with a /21 mask and has naturally handed it over to you at this point.   How many subnets does this leave you to work with?


Options are :

  • 128
  • 62
  • 16
  • 126
  • 14
  • 64
  • 30
  • 32

Answer :32

The decimal 237 is represented by which of the following binary strings?


Options are :

  • 11111000
  • 11101101
  • 11100010
  • 11100111
  • 11101111
  • 11110011

Answer :11101101

Which of these subnets contains the IP address 163.14.89.213 /19?


Options are :

  • 163.14.16.0 /19
  • 163.14.48.0 /19
  • 163.14.8.0 /19
  • 163.14.64.0 /19
  • 163.14.80.0 /19
  • 163.14.32.0 /19

Answer :163.14.64.0 /19

Practice : CCNA Cyber Ops - SECOPS # 210-255

Of the following three addresses, which are found on a common subnet?    The subnet mask for each address is 255.255.240.0.

Host A: 10.1.17.14 

Host B:  10.1.18.12

 Host C:  10.1.22.142


Options are :

  • They're all on the same subnet.
  • Host A and Host B are on a common subnet, but Host C does not share that subnet.
  • Host C and Host A are on a common subnet, but Host B does not share that subnet.
  • Host B and Host C are on a common subnet, but Host A does not share that subnet.
  • None of these hosts share a subnet with another named host.

Answer :They're all on the same subnet.

Given the network 39.0.0.0 and a subnet mask of 255.255.192.0, how many valid subnets will you have to work with?


Options are :

  • 1022
  • 0
  • 1024
  • 2048
  • 2
  • This is an illegal mask for this network.
  • 4
  • 2046

Answer :1024

How many valid host IP addresses exist on the 179.12.0.0 255.255.255.240 subnet?


Options are :

  • 62
  • 16
  • 64
  • 6
  • 30
  • 32
  • 14
  • 8

Answer :14

Mock : CCNA Cyber Ops - SECOPS # 210-255

What binary string correctly represents the decimal 77?


Options are :

  • 01000110
  • 01001110
  • 01001111
  • 01001101
  • 01110001
  • 01100000

Answer :01001101

Convert the binary string 00110110 to a decimal.


Options are :

  • 54
  • 39
  • 48
  • 49
  • 38
  • 50

Answer :54

The 200.1.3.0 network has been subnetted with a 255.255.255.252 mask.  How many valid addresses exist on each subnet?


Options are :

  • 128
  • 0
  • 4
  • 254
  • 126
  • 2
  • 256

Answer :2

Practice : CCNA Cyber Ops - SECOPS # 210-255

The three host addresses shown here are all in the default VLAN and each has a mask of 255.224.0.0.   Assuming no physical issues exist, which of these statements are true?

Host A:  10.66.1.1

Host B:  10.77.1.1

Host C:  10.88.1.1

Host D:  10.99.1.1


Options are :

  • Any of these hosts can ping the other, as they are all on the same subnet.
  • Hosts A and B will be able to ping each other, but any ping involving Host C or Host D will fail.
  • Hosts C and D can ping each other, but any ping involving Host A or Host B will fail.
  • Hosts B, C, and D will be able to ping each other, but pings involving Host A as a source or destination will fail.
  • Hosts A, B, and C will be able to ping each other, but pings involving Host D as a source or destination will fail.
  • As these four hosts are each on a different subnet, all pings will fail.

Answer :Hosts A, B, and C will be able to ping each other, but pings involving Host D as a source or destination will fail.

Convert the binary string 11110001 to a decimal.


Options are :

  • 87
  • 242
  • 239
  • 241
  • 99
  • 243
  • 212

Answer :241

Of these four addresses, which two share a common subnet?   Each address has a subnet mask of 255.255.255.240.

Host A:  200.1.1.126

Host B:  200.1.1.148

Host C:  200.1.1.155

Host D:  200.1.1.160


Options are :

  • Hosts A and B
  • Hosts A and C
  • These four hosts are found on four separate subnets.
  • Hosts B and C
  • All four hosts are on the same subnet.
  • Hosts C and D
  • Hosts B and D

Answer :Hosts B and C

Mock : CCNA Cyber Ops - SECFND # 210-250

What is the decimal equivalent of the binary string 01010101?


Options are :

  • 79
  • 127
  • 111
  • 66
  • 85
  • 89
  • 99

Answer :85

What subnet contains the IP address 214.38.242.123 /27?


Options are :

  • 214.38.242.32.0 /27
  • 214.38.242.0 /24
  • 214.38.242.122 /27
  • 214.38.242.64.0 /27
  • 214.38.242.120 /27
  • 214.38.242.96 /27

Answer :214.38.242.96 /27

Which of these binary strings represents the decimal 138?


Options are :

  • 10000111
  • 10001111
  • 10001011
  • 10001110
  • 10000101
  • 10001010

Answer :10001010

Mock : CCNA Cyber Ops - SECOPS # 210-255

Which of these binary strings accurately represents the decimal 199?


Options are :

  • 11001111
  • 11000011
  • 11000001
  • 11000111
  • 11011111

Answer :11000111

Given the following network and mask, how many valid addresses will be available on each subnet?

142.14.0.0 /25



Options are :

  • 126
  • 256
  • 254
  • 128
  • 4
  • 2
  • 6
  • 8

Answer :126

Upon which of the following subnets will the 11.9.248.7 /14 address be found?


Options are :

  • 11.8.0.0 /14
  • 11.9.128.0 /14
  • 11.9.0.0 /14
  • 11.0.0.0 /14
  • 11.1.0.0 /14

Answer :11.8.0.0 /14

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